1=(x/(84.5))^2+(y/(33.5))^2

解

1 = (\frac{x}{84.5})^{2} + (\frac{y}{33.5})^{2}

(h, k) = (0, 0), a = 84.5, b = 33.5

解答ステップ

1 = (\frac{x}{84.5})^{2} + (\frac{y}{33.5})^{2}

1 - (\frac{x}{84.5})^{2} - (\frac{y}{33.5})^{2} = 0

を標準的な楕円のequationの形式で書き換える

\frac{( x - 0 ) ^{2}}{84. 5 ^{2}} + \frac{( y - 0 ) ^{2}}{33. 5 ^{2}} = 1

ゆえに楕円の特性は:

(h, k) = (0, 0), a = 84.5, b = 33.5

a > b

ゆえに

a

は半長径,

b

は半短径である

中心が (h, k) = (0, 0), a = 84.5, b = 33.5 の楕円