(((x-2)^2))/4+(((y+4)^2))/(16)=1

Lösung

\frac{( ( x - 2 ) ^{2} )}{4} + \frac{( ( y + 4 ) ^{2} )}{16} = 1

(h, k) = (2, - 4), a = 2, b = 4

Schritte zur Lösung

\frac{( x - 2 ) ^{2}}{4} + \frac{( y + 4 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{4} + \frac{( y + 4 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 4 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 4), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, - 4), b = 4, a = 2

36 X^{2} + 25 Y^{2} = 900

1 x^{2} + 3 y^{2} + 8 x + 9 y - 14 = 0

2 x^{2} + y^{2} + x + y = 0

9 x^{2} + 18 x + 25 y^{2} - 100 y = 116

\frac{( x ^{2} - y ^{2} - 1 )}{2} = x^{2} + y^{2} - 1