(x+1)^2=16y

Lösung

(x + 1)^{2} = 16 y

(h, k) = (- 1, 0), p = 4

Schritte zur Lösung

(x + 1)^{2} = 16 y

Rewrite

(x + 1)^{2} = 16 y

in the standard form:

4 \cdot 4 (y - 0) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, 0), p = 4

2 x^{2} - 8 y + 4 = 0

x^{2} + 6 x - 2 y = 0

- f (x) = 3 x^{2} + 3 x - 2

y^{2} + 1 = x

3 y = x^{2}