-4y^2-12y+1=3x-5

Lösung

- 4 y^{2} - 12 y + 1 = 3 x - 5

(h, k) = (5, - \frac{3}{2}), p = - \frac{3}{16}

Schritte zur Lösung

- 4 y^{2} - 12 y + 1 = 3 x - 5

Rewrite

- 4 y^{2} - 12 y + 1 = 3 x - 5

in the standard form

4 (- \frac{3}{16}) (x - 5) = (y - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (5, - \frac{3}{2}), p = - \frac{3}{16}

- y^{2} - 6 x = 0

2 x + y^{2} = 48

3 x^{2} + y = 4

(y + 4) = 4 \cdot 3.5 \cdot (x - 3)^{2}

x - y^{2} = 7