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Beliebt Geometry >

center ((x-5)^2)/4+((y+3)^2)/(16)=1

Lösung

center

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

Lösung

(5, - 3)

Schritte zur Lösung

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 5 ) ^{2}}{2 ^{2}} + \frac{( y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (5, - 3), a = 2, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (5, - 3), b = 4, a = 2

And the center is:

(5, - 3)

Graph

Beliebte Beispiele

center 12x^2+20y^2-12x+40y-37=0

ce n t er 12 x^{2} + 20 y^{2} - 12 x + 40 y - 37 = 0

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ce n t er 2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

center 25x^2+144y^2=900

ce n t er 25 x^{2} + 144 y^{2} = 900

center 2x^2+y^2=50

ce n t er 2 x^{2} + y^{2} = 50

center ((x-h)^2)/(a^2)+((y-k)^2)/(b^2)=1

ce n t er \frac{( x - h ) ^{2}}{a ^{2}} + \frac{( y - k ) ^{2}}{b ^{2}} = 1