center x^2+36y^2-16x-72y+64=0

Lösung

center

x^{2} + 36 y^{2} - 16 x - 72 y + 64 = 0

(8, 1)

Schritte zur Lösung

x^{2} + 36 y^{2} - 16 x - 72 y + 64 = 0

Rewrite

x^{2} + 36 y^{2} - 16 x - 72 y + 64 = 0

in the form of the standard ellipse equation

\frac{( x - 8 ) ^{2}}{6 ^{2}} + \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (8, 1), a = 6, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (8, 1), a = 6, b = 1

And the center is:

(8, 1)

ce n t er 9 X^{2} + 4 Y^{2} = 36

ce n t er 2 x^{2} + y^{2} - 2 x + 16 y + 1 = 0

ce n t er 25 x^{2} + 16 y^{2} - 150 x + 128 y + 81 = 0

ce n t er 16 x^{2} + 4 y^{2} - 32 x + 24 y - 12 = 0

ce n t er x^{2} + y^{2} - 10 y = 0