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Beliebt Geometry >

center x^2+10x+9y^2+16=0

Lösung

center

x^{2} + 10 x + 9 y^{2} + 16 = 0

Lösung

(- 5, 0)

Schritte zur Lösung

x^{2} + 10 x + 9 y^{2} + 16 = 0

Rewrite

x^{2} + 10 x + 9 y^{2} + 16 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 5 ) ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 5, 0), a = 3, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 5, 0), a = 3, b = 1

And the center is:

(- 5, 0)

Graph

Beliebte Beispiele

center 9x^2+16y^2-18x-64y-71=0

ce n t er 9 x^{2} + 16 y^{2} - 18 x - 64 y - 71 = 0

center 3x^2+4y^2+24x-16y+52=0

ce n t er 3 x^{2} + 4 y^{2} + 24 x - 16 y + 52 = 0

center (y^2}{16}+\frac{x^2)/9 =1

ce n t er \frac{y ^{2}}{16} + \frac{x ^{2}}{9} = 1

center 9x^2+4y^2-18x+8y-23=0

ce n t er 9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0

center (x^2)/9+(y^2)/(36)=1

ce n t er \frac{x ^{2}}{9} + \frac{y ^{2}}{36} = 1