center 20x^2-16y^2-40x128x-556=0

Lösung

center

20 x^{2} - 16 y^{2} - 40 x 128 x - 556 = 0

(0, 0)

Schritte zur Lösung

20 x^{2} - 16 y^{2} - 40 x \cdot 128 x - 556 = 0

Rewrite

20 x^{2} - 16 y^{2} - 40 x 128 x - 556 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{139}{5 51} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{139}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{139}{5 51}, b = \frac{139}{2}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{139}{2}, a = \frac{139}{5 51}

And the center is:

(0, 0)

ce n t er 9 x^{2} + 16 y^{2} + 126 x + 96 y + 441 = 0

ce n t er 5 x^{2} + 9 y^{2} - 10 x + 4 = 0

ce n t er 3 x^{2} + 4 y^{2} = 12

ce n t er 25 (x - 2)^{2} + 9 (y + 3)^{2} = 225

ce n t er \frac{( x + 5 ) ^{2}}{5} + \frac{( y + 3 ) ^{2}}{3} = 1