exzentrizität 3x^2+6y^2=18

Lösung

exzentrizität

3 x^{2} + 6 y^{2} = 18

\frac{1}{2}

Dezimale

0.70710 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

3 x^{2} + 6 y^{2} = 18 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 3

= \frac{( 6 ) ^{2} - ( 3 ) ^{2}}{6}

\frac{( 6 ) ^{2} - ( 3 ) ^{2}}{6} = \frac{1}{2}

= \frac{1}{2}

ecce n t r i c i t y 9 x^{2} + 16 y^{2} - 54 x + 64 y + 1 = 0

ecce n t r i c i t y 4 x^{2} + 9 y^{2} = 36

ecce n t r i c i t y 4 x^{2} + 3 y^{2} - 24 x + 18 y + 51 = 0

ecce n t r i c i t y \frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

ecce n t r i c i t y \frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1