achse 25x^2+4y^2=100

Lösung

achse

25 x^{2} + 4 y^{2} = 100

semi - major axis b = 5, semi - minor axis a = 2

Schritte zur Lösung

25 x^{2} + 4 y^{2} = 100

Rewrite

25 x^{2} + 4 y^{2} = 100

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 2

a x i s 36 x^{2} + 288 x + 64 y^{2} - 256 y = 1472

a x i s \frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

a x i s 9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0

a x i s \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

a x i s \frac{( x - 2 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{25} = 1