y^2=-2Bx

Lösung

y^{2} = - 2 B x

(h, k) = (0, 0), p = - \frac{B}{2}

Schritte zur Lösung

y^{2} = - 2 B x

Rewrite

y^{2} = - 2 B x

in the standard form:

4 (- \frac{B}{2}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{B}{2}

(y + 9)^{2} - 2 (x - 4) = 0

x = y^{2} + 4 y + 3

x^{2} + 8 y - 16 = 0

x^{2} - 10 x + k (x) = 0

x^{2} + 2 x + m (x) + 1 = 0