(x^2)/9-(y^2)/(40)=1

解答

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

(h, k) = (0, 0), a = 3, b = 210

求解步骤

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

将

\frac{x ^{2}}{9} - \frac{y ^{2}}{40} = 1

改写为标准双曲线方程形式

\frac{( x - 0 ) ^{2}}{3 ^{2}} - \frac{( y - 0 ) ^{2}}{( 2 10 ) ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = 3, b = 210

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{9} = - 1

y^{2} = x^{2} + 2

117 x^{2} - 52 y^{2} + 702 x - 208 y + 1169 = 0

\frac{( y - 3 ) ^{2}}{9} - x^{2} = 1