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受欢迎的 Geometry >

x^2-20x+(10p(x)+10)=0

解答

x^{2} - 20 x + (10 p (x) + 10) = 0

解答

x = \frac{20 - 10 p + 100 p ^{2} - 400 p + 360}{2}, x = \frac{20 - 10 p - 100 p ^{2} - 400 p + 360}{2}

求解步骤

x^{2} - 20 x + (10 p (x) + 10) = 0

整理后得

x^{2} - 20 x + 10 p x + 10 = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} + (- 20 + 10 p) x + 10 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 20 + 10 p ) \pm ( - 20 + 10 p ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

化简

(- 20 + 10 p)^{2} - 4 \cdot 1 \cdot 10 : 100 p^{2} - 400 p + 360

x_{1, 2} = \frac{- ( - 20 + 10 p ) \pm 100 p ^{2} - 400 p + 360}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 20 + 10 p ) + 100 p ^{2} - 400 p + 360}{2 \cdot 1}, x_{2} = \frac{- ( - 20 + 10 p ) - 100 p ^{2} - 400 p + 360}{2 \cdot 1}

x = \frac{- ( - 20 + 10 p ) + 100 p ^{2} - 400 p + 360}{2 \cdot 1} : \frac{20 - 10 p + 100 p ^{2} - 400 p + 360}{2}

x = \frac{- ( - 20 + 10 p ) - 100 p ^{2} - 400 p + 360}{2 \cdot 1} : \frac{20 - 10 p - 100 p ^{2} - 400 p + 360}{2}

二次方程组的解是:

x = \frac{20 - 10 p + 100 p ^{2} - 400 p + 360}{2}, x = \frac{20 - 10 p - 100 p ^{2} - 400 p + 360}{2}

作图

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