(x+3)^2=4(y+4)

Lösung

(x + 3)^{2} = 4 (y + 4)

(h, k) = (- 3, - 4), p = 1

Schritte zur Lösung

(x + 3)^{2} = 4 (y + 4)

Rewrite

(x + 3)^{2} = 4 (y + 4)

in the standard form:

4 \cdot 1 \cdot (y - (- 4)) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, - 4), p = 1

x = y^{2} + 6 y + 8

(x + 3)^{2} = - 4 (y - 2)

4 x - y^{2} + 5 = 0

x^{2} + 10 x + 12 y + 1 = 0

- 8 x = y^{2} - 6 x + 49