4x^2-4y^2-2x+8y-4=0

解

4 x^{2} - 4 y^{2} - 2 x + 8 y - 4 = 0

(h, k) = (\frac{1}{4}, 1), a = \frac{1}{4}, b = \frac{1}{4}

解答ステップ

4 x^{2} - 4 y^{2} - 2 x + 8 y - 4 = 0

4 x^{2} - 4 y^{2} - 2 x + 8 y - 4 = 0

を標準的な双曲線のequationで書き換える

\frac{( x - \frac{1}{4} ) ^{2}}{( \frac{1}{4} ) ^{2}} - \frac{( y - 1 ) ^{2}}{( \frac{1}{4} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (\frac{1}{4}, 1), a = \frac{1}{4}, b = \frac{1}{4}