3y^2-12x^2-36y-48x+48=0

解答

3 y^{2} - 12 x^{2} - 36 y - 48 x + 48 = 0

(h, k) = (- 2, 6), a = 2, b = 1

求解步骤

3 y^{2} - 12 x^{2} - 36 y - 48 x + 48 = 0

将

3 y^{2} - 12 x^{2} - 36 y - 48 x + 48 = 0

改写为标准双曲线方程形式

\frac{( y - 6 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{1 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (- 2, 6), a = 2, b = 1