y^2+2y-x=0

Lösung

y^{2} + 2 y - x = 0

(h, k) = (- 1, - 1), p = \frac{1}{4}

Schritte zur Lösung

y^{2} + 2 y - x = 0

Rewrite

y^{2} + 2 y - x = 0

in the standard form

4 \cdot \frac{1}{4} (x - (- 1)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 1), p = \frac{1}{4}

(y - 4)^{2} = (x - 3)

y = 2 (x - 5)^{2} + 3

(y - 2)^{2} = x - 1

y^{2} - 6 y - 3 x + 8 = 0

(y - 2)^{2} = 4 (x + 1)