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Beliebt Geometry >

-x^2+2x+4y^2+24y+31=0

Lösung

- x^{2} + 2 x + 4 y^{2} + 24 y + 31 = 0

Lösung

(h, k) = (1, - 3), a = 1, b = 2

Schritte zur Lösung

- x^{2} + 2 x + 4 y^{2} + 24 y + 31 = 0

Rewrite

- x^{2} + 2 x + 4 y^{2} + 24 y + 31 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 3 ) ) ^{2}}{1 ^{2}} - \frac{( x - 1 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 3), a = 1, b = 2

Graph

Beliebte Beispiele

9 x^{2} - 9 y^{2} = 9

(x + y) (x - y) = 119

y^2-4x^2-4y+24x=48

y^{2} - 4 x^{2} - 4 y + 24 x = 48

x^2-4y^2+2x-16y-19=0

x^{2} - 4 y^{2} + 2 x - 16 y - 19 = 0

(x^2-4x)-(y^2+4y)=1

(x^{2} - 4 x) - (y^{2} + 4 y) = 1