((x+4)^2)/(64)-((y+5)^2)/(81)=1

解答

\frac{( x + 4 ) ^{2}}{64} - \frac{( y + 5 ) ^{2}}{81} = 1

(h, k) = (- 4, - 5), a = 8, b = 9

求解步骤

\frac{( x + 4 ) ^{2}}{64} - \frac{( y + 5 ) ^{2}}{81} = 1

将

\frac{( x + 4 ) ^{2}}{64} - \frac{( y + 5 ) ^{2}}{81} = 1

改写为标准双曲线方程形式

\frac{( x - ( - 4 ) ) ^{2}}{8 ^{2}} - \frac{( y - ( - 5 ) ) ^{2}}{9 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (- 4, - 5), a = 8, b = 9

3 x^{(2)} - 12 y^{(2)} + 48 = 0

- 9 y^{2} + z^{2} = 36

3 x^{2} - y^{2} + 3 x + 4 y - 3 = 0

\frac{( x - 3 ) ^{2}}{10} - \frac{( y + 5 ) ^{2}}{9} = 4

so l v e f or x, 12 Y (x)^{2} - 15 x^{2} = 180