y<= x^2-1

Lösung

y \leq x^{2} - 1

(h, k) = (0, - 1), p = \frac{1}{4}

Schritte zur Lösung

y \leq x^{2} - 1

Rewrite

y \leq x^{2} - 1

in the standard form:

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 1), p = \frac{1}{4}

y \leq x^{2} - 5

y - 7 x^{2} = 6

y^{2} - x - 1 = 0

- f (x) = x^{2} + x + 1

x^{2} + 8 y + 8 x = 0