y2y=4x+10

Lösung

y 2 y = 4 x + 10

(h, k) = (- \frac{5}{2}, 0), p = \frac{1}{2}

Schritte zur Lösung

y \cdot 2 y = 4 x + 10

Rewrite

y \cdot 2 y = 4 x + 10

in the standard form

4 \cdot \frac{1}{2} (x - (- \frac{5}{2})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{2}, 0), p = \frac{1}{2}

x^{2} + 28 = - 6 y - 8 x

x - 9 = y^{2}

y^{2} - 5 y - 7 x - 3 = 0

p (x) \frac{( x )}{x ^{2}} - 4 x + 4 = 0

y^{2} - 8 x - 6 y + 17 = 0