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Beliebt Geometry >

center 4x^2-9y^2+32x+36y+64=0

Lösung

center

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

Lösung

(- 4, 2)

Schritte zur Lösung

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

Rewrite

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{2 ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 2), a = 2, b = 3

And the center is:

(- 4, 2)

Graph

Beliebte Beispiele

center 4x^2-45y^2=180

center ((y-2)^2)/9-((x-1)^2)/(16)=1

center (x^2}{36}-\frac{y^2)/9 =1

center x^2-y^2-2x-4y=-4

center 9y^2-4x^2=36