center ((x+2)^2}{16}-\frac{(y-1)^2)/9 =1

Lösung

center

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 1 ) ^{2}}{9} = 1

(- 2, 1)

Schritte zur Lösung

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 1 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 1 ) ^{2}}{9} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 2 ) ) ^{2}}{4 ^{2}} - \frac{( y - 1 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 1), a = 4, b = 3

And the center is:

(- 2, 1)

ce n t er \frac{x ^{2}}{289} - \frac{y ^{2}}{144} = 1

ce n t er \frac{y ^{2}}{4} - \frac{x ^{2}}{1} = 1

ce n t er 121 - 32 x - 8 x^{2} - 90 y + 9 y^{2} = 0

ce n t er y^{2} - 4 x^{2} = 36

ce n t er 10 x^{2} - 6 y^{2} - 20 x - 24 y + 46 = 0