exzentrizität 18x^2-32y^2-108y-128x-254=0

Lösung

exzentrizität

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0

\frac{5}{4}

Dezimale

1.25

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0 :

Right-left Hyperbola with

(h, k) = (\frac{32}{9}, - \frac{27}{16}), a = \frac{28111}{36}, b = \frac{28111}{48}

= \frac{( \frac{28111}{36} ) ^{2} + ( \frac{28111}{48} ) ^{2}}{\frac{28111}{36}}

Fasse zusammen

= \frac{5}{4}