exzentrizität ((x+1)^2)/4-(y-5)^2=4

Lösung

exzentrizität

\frac{( x + 1 ) ^{2}}{4} - (y - 5)^{2} = 4

\frac{5}{2}

Dezimale

1.11803 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{( x + 1 ) ^{2}}{4} - (y - 5)^{2} = 4 :

Right-left Hyperbola with

(h, k) = (- 1, 5), a = 4, b = 2

= \frac{4 ^{2} + 2 ^{2}}{4}

Fasse zusammen

= \frac{5}{2}

ecce n t r i c i t y 9 x^{2} - 16 y^{2} = 144

ecce n t r i c i t y \frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

ecce n t r i c i t y 9 y^{2} - 49 x^{2} = 441

ecce n t r i c i t y 9 x^{2} - 18 x - 16 y^{2} - 64 y = 199

ecce n t r i c i t y \frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1