x^2-4y-12x+68=0

Lösung

x^{2} - 4 y - 12 x + 68 = 0

(h, k) = (6, 8), p = 1

Schritte zur Lösung

x^{2} - 4 y - 12 x + 68 = 0

Rewrite

x^{2} - 4 y - 12 x + 68 = 0

in the standard form

4 \cdot 1 \cdot (y - 8) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, 8), p = 1

x^{2} - 8 x + 8 y + 16 = 0

y = x^{2} + 12 x + 16

- y = 9 - x^{2}

x - 3 = - (y + 5)^{2}

x - y^{2} = - 4