2f(x)=x^2-5x+4

解

2 f (x) = x^{2} - 5 x + 4

(h, k) = (\frac{5}{2}, - \frac{9}{8}), p = \frac{1}{2}

解答ステップ

2 y = x^{2} - 5 x + 4

2 y = x^{2} - 5 x + 4

を標準的な形式で書き換える

4 \cdot \frac{1}{2} (y - (- \frac{9}{8})) = (x - \frac{5}{2})^{2}

ゆえに放物線の特性は:

(h, k) = (\frac{5}{2}, - \frac{9}{8}), p = \frac{1}{2}