2x+y^2-8-y=0

Lösung

2 x + y^{2} - 8 - y = 0

(h, k) = (\frac{33}{8}, \frac{1}{2}), p = - \frac{1}{2}

Schritte zur Lösung

2 x + y^{2} - 8 - y = 0

Rewrite

2 x + y^{2} - 8 - y = 0

in the standard form

4 (- \frac{1}{2}) (x - \frac{33}{8}) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{33}{8}, \frac{1}{2}), p = - \frac{1}{2}

x^{2} = 3 y - 4

x = y^{2} + y

x - y^{2} + 2 = y - x

x^{2} - 60 y - 4000 = 0

y^{1} = - 0.45 x^{2} + x + 6