3x^2-y+6=0

Lösung

3 x^{2} - y + 6 = 0

(h, k) = (0, 6), p = \frac{1}{12}

Schritte zur Lösung

3 x^{2} - y + 6 = 0

Rewrite

3 x^{2} - y + 6 = 0

in the standard form:

4 \cdot \frac{1}{12} (y - 6) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 6), p = \frac{1}{12}

x^{2} - 2 x + 4 y - 11 = 0

\frac{1}{x} + \frac{1}{x y} = \frac{x}{y}

(x - 0)^{2} = - 8 (y - 1)

x^{2} + 6 x + 1 - 4 y = 0

y^{2} + z = 0