2f(x)=5x^2-x+2

Lösung

2 f (x) = 5 x^{2} - x + 2

(h, k) = (\frac{1}{10}, \frac{39}{40}), p = \frac{1}{10}

Schritte zur Lösung

2 y = 5 x^{2} - x + 2

Rewrite

2 y = 5 x^{2} - x + 2

in the standard form

4 \cdot \frac{1}{10} (y - \frac{39}{40}) = (x - \frac{1}{10})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{10}, \frac{39}{40}), p = \frac{1}{10}

2 f (x) = 5 x^{2} - x + 4

x - y^{2} + y + 1 = 0

9 y^{2} - 18 x + 4 y^{2} = 27

2 x^{2} + 4 y - 8 = 0

5 x^{2} + 4 y = 20