y^2=4(1/4)x

Lösung

y^{2} = 4 (\frac{1}{4}) x

(h, k) = (0, 0), p = \frac{1}{4}

Schritte zur Lösung

y^{2} = 4 \cdot \frac{1}{4} x

Rewrite

y^{2} = 4 \cdot \frac{1}{4} x

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{4}

x^{2} = 4 - 2 y

x^{2} + 3 y = 9

(y - 4)^{2} = 20 (x - 7)

\frac{1}{7} (y - 15) = (x + 3)^{2}

yy - (- 4) = 3 (x - (- 2))