-4x+x^2+2y+4=0

Lösung

- 4 x + x^{2} + 2 y + 4 = 0

(h, k) = (2, 0), p = - \frac{1}{2}

Schritte zur Lösung

- 4 x + x^{2} + 2 y + 4 = 0

Rewrite

- 4 x + x^{2} + 2 y + 4 = 0

in the standard form

4 (- \frac{1}{2}) (y - 0) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 0), p = - \frac{1}{2}

2 x - 4 y^{2} = 3

3 x^{2} + 5 y = 0

(x - 3)^{2} = 12 y

x^{2} + 10 x - 10 y + 5 = 0

k (x) - 1 (x) = x^{2} + 5