y^2-6y-12x-39=0

Lösung

y^{2} - 6 y - 12 x - 39 = 0

(h, k) = (- 4, 3), p = 3

Schritte zur Lösung

y^{2} - 6 y - 12 x - 39 = 0

Rewrite

y^{2} - 6 y - 12 x - 39 = 0

in the standard form

4 \cdot 3 (x - (- 4)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 3), p = 3

x^{2} - 10 y = 0

x^{2} - 10 x - 35 y = - 25 - 35

(x - 2)^{2} = 4 (y - 1)

x = \frac{1}{4} (y^{2})

(y + 1)^{2} = x