3y^2-1=2x

Lösung

3 y^{2} - 1 = 2 x

(h, k) = (- \frac{1}{2}, 0), p = \frac{1}{6}

Schritte zur Lösung

3 y^{2} - 1 = 2 x

Rewrite

3 y^{2} - 1 = 2 x

in the standard form:

4 \cdot \frac{1}{6} (x - (- \frac{1}{2})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, 0), p = \frac{1}{6}

2 x^{2} - 5 x + 7 y - 9 = 0

y - y^{2} = x

(y + 1)^{2} = 4 (x + 3)

4 x^{2} + x + m (x) = 0

(x + 5)^{2} = 8 (y + 7)