18y^2-24y+36x-1=0

解

18 y^{2} - 24 y + 36 x - 1 = 0

(h, k) = (\frac{1}{4}, \frac{2}{3}), p = - \frac{1}{2}

解答ステップ

18 y^{2} - 24 y + 36 x - 1 = 0

18 y^{2} - 24 y + 36 x - 1 = 0

を標準的な形式で書き換える

4 (- \frac{1}{2}) (x - \frac{1}{4}) = (y - \frac{2}{3})^{2}

ゆえに放物線の特性は:

(h, k) = (\frac{1}{4}, \frac{2}{3}), p = - \frac{1}{2}