r^2-7t+6=0

Lösung

r^{2} - 7 t + 6 = 0

(h, k) = (0, \frac{6}{7}), p = \frac{7}{4}

Schritte zur Lösung

r^{2} - 7 t + 6 = 0

Rewrite

r^{2} - 7 t + 6 = 0

in the standard form:

4 \cdot \frac{7}{4} (t - \frac{6}{7}) = (r - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{6}{7}), p = \frac{7}{4}

x = 3 y^{2} - 1

2 (y + 5) = (x + 1)^{2}

5 x^{2} + 4 (y + 5) = 80

\frac{x ^{2}}{36} = 9 y

y = x^{2} + 5 y