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Beliebt Geometry >

x^2+y^2<= 16

Lösung

x^{2} + y^{2} \leq 16

Lösung

(a, b) = (0, 0), r = 4

Schritte zur Lösung

x^{2} + y^{2} \leq 16

Rewrite

x^{2} + y^{2} \leq 16

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 4

Graph

Beliebte Beispiele

scheitelpunkte f(x)=x^2+4x

v er t i ces f (x) = x^{2} + 4 x

foki (x^2)/4+(y^2)/(25)=1

f oc i \frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

2 x - y^{2} = 0

\frac{x ^{2}}{4} + y^{2} = 1

x^{2} + (y - 2)^{2} = 1