x^2= 18/5 (y+10)

解答

x^{2} = \frac{18}{5} (y + 10)

(h, k) = (0, - 10), p = \frac{9}{10}

求解步骤

x^{2} = \frac{18}{5} (y + 10)

将

x^{2} = \frac{18}{5} (y + 10)

改写为标准形式:

4 \cdot \frac{9}{10} (y - (- 10)) = (x - 0)^{2}

因此抛物线性质是:

(h, k) = (0, - 10), p = \frac{9}{10}

6 y = x^{2} + \frac{1}{2}

y = - 0.508 x^{2} + 12.8 x + (- 65.8)

y + 9 = \frac{3}{2} (x + 2) 23 (x + 2)

x^{2} + 4 y + 4 x = 0

(y - 1)^{2} - x = 3