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受欢迎的 Geometry >

solvefor x,(1-t(x))=3x^2-4x+25

解答

求解

x, (1 - t (x)) = 3 x^{2} - 4 x + 25

解答

x = \frac{- t + 4 + t ^{2} - 8 t - 272}{6}, x = \frac{- t + 4 - t ^{2} - 8 t - 272}{6}

求解步骤

(1 - t (x)) = 3 x^{2} - 4 x + 25

整理后得

1 - x t = 3 x^{2} - 4 x + 25

交换两边

3 x^{2} - 4 x + 25 = 1 - x t

将

x t

para o lado esquerdo

3 x^{2} - 4 x + 25 + x t = 1

将

1

para o lado esquerdo

3 x^{2} + x t - 4 x + 24 = 0

改写成标准形式

a x^{2} + b x + c = 0

3 x^{2} + (t - 4) x + 24 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( t - 4 ) \pm ( t - 4 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

化简

(t - 4)^{2} - 4 \cdot 3 \cdot 24 : t^{2} - 8 t - 272

x_{1, 2} = \frac{- ( t - 4 ) \pm t ^{2} - 8 t - 272}{2 \cdot 3}

将解分隔开

x_{1} = \frac{- ( t - 4 ) + t ^{2} - 8 t - 272}{2 \cdot 3}, x_{2} = \frac{- ( t - 4 ) - t ^{2} - 8 t - 272}{2 \cdot 3}

x = \frac{- ( t - 4 ) + t ^{2} - 8 t - 272}{2 \cdot 3} : \frac{- t + 4 + t ^{2} - 8 t - 272}{6}

x = \frac{- ( t - 4 ) - t ^{2} - 8 t - 272}{2 \cdot 3} : \frac{- t + 4 - t ^{2} - 8 t - 272}{6}

二次方程组的解是:

x = \frac{- t + 4 + t ^{2} - 8 t - 272}{6}, x = \frac{- t + 4 - t ^{2} - 8 t - 272}{6}

作图

流行的例子

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5y^2-4x+10y+17=0

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