y<=-x^2+8x

Lösung

y \leq - x^{2} + 8 x

(h, k) = (4, 16), p = - \frac{1}{4}

Schritte zur Lösung

y \leq - x^{2} + 8 x

Rewrite

y \leq - x^{2} + 8 x

in the standard form

4 (- \frac{1}{4}) (y - 16) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 16), p = - \frac{1}{4}

Y^{2} - X + 8 Y + 13 = 0

2 x^{2} + 10 y - 1900 = 0

y^{2} - 4 x - 4 y = 4

y^{2} - 2 x - 8 y + 24 = 0

y^{2} + x - 5 = 0