y^2-4y-4x=0

Lösung

y^{2} - 4 y - 4 x = 0

(h, k) = (- 1, 2), p = 1

Schritte zur Lösung

y^{2} - 4 y - 4 x = 0

Rewrite

y^{2} - 4 y - 4 x = 0

in the standard form

4 \cdot 1 \cdot (x - (- 1)) = (y - 2)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 2), p = 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{49} = 1

v er t i ces \frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

a sy m pt o t es \frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

v er t i ces f (x) = x^{2} - 2 x + 4