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受欢迎的 Geometry >

solvefor x,-4h(x)^2+12x+16=0

解答

求解

x, - 4 h (x)^{2} + 12 x + 16 = 0

解答

x = - \frac{- 3 + 16 h + 9}{2 h}, x = \frac{16 h + 9 + 3}{2 h}; h \neq = 0

求解步骤

- 4 h x^{2} + 12 x + 16 = 0

使用求根公式求解

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 4 h ) \cdot 16}{2 ( - 4 h )}

化简

1 2^{2} - 4 (- 4 h) \cdot 16 : 4 9 + 16 h

x_{1, 2} = \frac{- 12 \pm 4 9 + 16 h}{2 ( - 4 h )}; h \neq = 0

将解分隔开

x_{1} = \frac{- 12 + 4 9 + 16 h}{2 ( - 4 h )}, x_{2} = \frac{- 12 - 4 9 + 16 h}{2 ( - 4 h )}

x = \frac{- 12 + 4 9 + 16 h}{2 ( - 4 h )} : - \frac{- 3 + 16 h + 9}{2 h}

x = \frac{- 12 - 4 9 + 16 h}{2 ( - 4 h )} : \frac{16 h + 9 + 3}{2 h}

二次方程组的解是:

x = - \frac{- 3 + 16 h + 9}{2 h}, x = \frac{16 h + 9 + 3}{2 h}; h \neq = 0

作图

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