x^2+10x-y=0

Lösung

x^{2} + 10 x - y = 0

(h, k) = (- 5, - 25), p = \frac{1}{4}

Schritte zur Lösung

x^{2} + 10 x - y = 0

Rewrite

x^{2} + 10 x - y = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- 25)) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 25), p = \frac{1}{4}

x = a t^{2}

6 = a b^{- 2}

- 4 x^{2} + 8 y + 64 = 0

3 (x + \frac{3}{4}) + 3 (y - \frac{1}{2})^{2} = 36

x = - 5 (\frac{y + 9}{4})^{2}