f(x)(x)^{-1}=(x+4)/3

解答

f (x) (x)^{- 1} = \frac{x + 4}{3}

(h, k) = (- 2, - \frac{4}{3}), p = \frac{3}{4}

求解步骤

y x^{- 1} = \frac{x + 4}{3}

将

y x^{- 1} - \frac{x + 4}{3} = 0

改写为标准形式

4 \cdot \frac{3}{4} (y - (- \frac{4}{3})) = (x - (- 2))^{2}

因此抛物线性质是:

(h, k) = (- 2, - \frac{4}{3}), p = \frac{3}{4}

x^{2} - 8 m (x) - 32 x + 5 m (x) - 8 = 0

(x + 3)^{2} = - \frac{1}{2} (y - 1)

\frac{y}{x} + \frac{70 - y}{x + 10} = 6

x^{2} - 40 y = - 200

- y^{2} - 2 x = 4