x^2+8=12y+4

Lösung

x^{2} + 8 = 12 y + 4

(h, k) = (0, \frac{1}{3}), p = 3

Schritte zur Lösung

x^{2} + 8 = 12 y + 4

Rewrite

x^{2} + 8 = 12 y + 4

in the standard form:

4 \cdot 3 (y - \frac{1}{3}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{1}{3}), p = 3

\frac{y}{xx} = 1

- 3 x^{2} = - 5 z + 4

(y - 4)^{(2)} = 4 (x - 3)

y > x^{2} + 2 x - 5

y^{2} = - 4 p (x - h)