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Beliebt Geometry >

foki 0=(y-1)^2-16(x+4)

Lösung

foki

0 = (y - 1)^{2} - 16 (x + 4)

Lösung

(0, 1)

Schritte zur Lösung

Rewrite

0 = (y - 1)^{2} - 16 (x + 4)

in the standard form:

4 \cdot 4 (x - (- 4)) = (y - 1)^{2}

(h, k) = (- 4, 1), p = 4

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- 4, 1)

along the x-axis

(- 4 + p, 1)

= (- 4 + 4, 1)

Fasse zusammen

(0, 1)

Graph

Beliebte Beispiele

f oc i - 16 t^{2} + 256

foki 2x^2+8x-24

f oc i 2 x^{2} + 8 x - 24

f oc i 10 y^{2} = 22 x

foki y=(-3x^2-2x+6)/5

f oc i y = \frac{- 3 x ^{2} - 2 x + 6}{5}

foki y=x^2+2x+3

f oc i y = x^{2} + 2 x + 3