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Beliebt Geometry >

foki x^2+20y=10

Lösung

foki

x^{2} + 20 y = 10

Lösung

(0, - \frac{9}{2})

Schritte zur Lösung

Rewrite

x^{2} + 20 y = 10

in the standard form:

4 (- 5) (y - \frac{1}{2}) = (x - 0)^{2}

(h, k) = (0, \frac{1}{2}), p = - 5

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, \frac{1}{2})

along the y-axis

(0, \frac{1}{2} + p)

= (0, \frac{1}{2} + (- 5))

Fasse zusammen

(0, - \frac{9}{2})

Graph

Beliebte Beispiele

f oc i 7 y^{2}

f oc i \frac{1}{2} x^{2}

foki y^2-2y-12x+25=0

f oc i y^{2} - 2 y - 12 x + 25 = 0

f oc i (x - 6)^{2} + 8

foki y= 1/12 x^2

f oc i y = \frac{1}{12} x^{2}