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Beliebt Geometry >

foki (y-2)^2+16(x-3)=0

Lösung

foki

(y - 2)^{2} + 16 (x - 3) = 0

Lösung

(- 1, 2)

Schritte zur Lösung

Rewrite

(y - 2)^{2} + 16 (x - 3) = 0

in the standard form:

4 (- 4) (x - 3) = (y - 2)^{2}

(h, k) = (3, 2), p = - 4

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(3, 2)

along the x-axis

(3 + p, 2)

= (3 + (- 4), 2)

Fasse zusammen

(- 1, 2)

Graph

Beliebte Beispiele

f oc i z^{2} + 10 z + 5

f oc i - 3 x^{2} + 3

foki y^2+14y+4x+45=0

f oc i y^{2} + 14 y + 4 x + 45 = 0

f oc i + (x + 2)^{2} - 4

foki y=((-6(r+4r^2)+9r^2+6r)^2)/(9r^2)

f oc i y = \frac{( - 6 ( r + 4 r ^{2} ) + 9 r ^{2} + 6 r ) ^{2}}{9 r ^{2}}