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Beliebt Geometry >

foki y=28x^2+47x+15

Lösung

foki

y = 28 x^{2} + 47 x + 15

Lösung

(- \frac{47}{56}, - \frac{33}{7})

Schritte zur Lösung

Rewrite

y = 28 x^{2} + 47 x + 15

in the standard form

4 \cdot \frac{1}{112} (y - (- \frac{529}{112})) = (x - (- \frac{47}{56}))^{2}

(h, k) = (- \frac{47}{56}, - \frac{529}{112}), p = \frac{1}{112}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{47}{56}, - \frac{529}{112})

along the y-axis

(- \frac{47}{56}, - \frac{529}{112} + p)

= (- \frac{47}{56}, - \frac{529}{112} + \frac{1}{112})

Fasse zusammen

(- \frac{47}{56}, - \frac{33}{7})

Graph

Beliebte Beispiele

foki y=x^2-4x+4

f oc i y = x^{2} - 4 x + 4

f oc i y^{2} + 36 x = 0

f oc i \frac{x ^{2}}{2}

f oc i x^{2} + x + 5

f oc i x^{2} + x - 9