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Beliebt Geometry >

foki+4t^2

Lösung

foki

+ 4 t^{2}

Lösung

(0, \frac{1}{16})

Schritte zur Lösung

Rewrite

y = 4 t^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (t - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{16})

Fasse zusammen

(0, \frac{1}{16})

Graph

Beliebte Beispiele

foki (-4x-11)^2

f oc i (- 4 x - 11)^{2}

f oc i 2 x^{2} - 8 x + 3

foki (x-3)(x+1)

f oc i (x - 3) (x + 1)

foki y=x^2+5x-24

f oc i y = x^{2} + 5 x - 24

foki y=-x^2+2x-5

f oc i y = - x^{2} + 2 x - 5